瑞高鋼琴 (Giuoco Piano)

侯逸凡 (Hóu Yìfán) – 赵骏 (Zhào Jùn)
44th Chinese Chess Championship; 兴化 (Xīnghuà), April 19, 2013
Giuoco Piano C54

1. e4 e5 2. Nf3 Nc6 3. Bc4 Bc5 4. c3 Nf6. The Damiano Variation (1512). 5. d4 exd4 6. e5. Inernational Master Giorgio Porreca, in his “Manuale Teorico-Pratico delle Aperture” (“Theoretical-Practical Handbook of Openings”), Mursia & C., Milan, 1971-1974, p. 120, considered “Steinitz’s move 6. e5 to be lapsed, not because bad in itself but because it is incapable of bringing objective difficulties to Black”. But 侯逸凡 (Hóu Yìfán) is not a blind believer... 6. ... d5 7. Be2. 7. Bb5 Ne4 is a “tabiya”, but as Porreca suggested (op. cit., p. 126), “The move [7. Bb5] can be replaced by 7. Be2, thus preventing the future pin on the f3-Knight”. 7. ... Ne4 8. cxd4

8. ... Nxd4?! A gambling Knight sacrifice with many incognitas. 8. ... Bb6 is the normal reply; for instance: 9. Nc3 0-0 10. Be3 Be6 11. Qc2 f5 12. exf6 Qxf6 13. Rd1 Rae8 14. 0-0 Ne7 15. Ne5 Nf5 16. Nxe4 dxe4 17. Qxe4 Bxa2 18. g4 Nxd4 19. Bxd4 Bxd4 20. Qxd4 Qxe5 21. Bc4+ Bxc4 22. Qxc4+ Qe6 23. Qxe6+ Rxe6 24. Rd7 Re2 25. Rc1 ½ : ½ Schlechter – Réti, Baden bei Wien 1914. 9. Nxd4 Nxf2 10. Kxf2 Qh4+ 11. g3 Bxd4+ 12. Be3. 12. Ke1!? Qe4 13. Rf1 might be more promising. 12. ... Bxe3+ 13. Kxe3 Qh6+ 14. Kf3

14. ... 0-0. 14. ... Be6?! 15. Qa4+ c6 16. Qh4 Qg6 17. Rf1 Qf5+ 18. Qf4 Qh3 19. Nd2 f6 20. Kf2 Qxh2+ 21. Ke1 0-0-0? 22. Nf3 Qh3 23. exf6 gxf6 24. Kf2 Qh5 25. Nd4 Qh2+ 26. Kf3 Qh5+ 27. Ke3 Qe8 28. Kd2 Bd7 29. Nb5 cxb5 30. Rac1+ Bc6 31. Bg4+ Rd7 32. Qd6 Qd8 33. Rxc6+ bxc6 34. Qxc6+ Kb8 35. Bxd7 Qa5+ 36. Kd3 a6 37. Qd6+ Qc7 38. Rxf6 Rg8 39. g4 h5 40. gxh5 Rg3+ 41. Kd4 Qxd6 42. Rxd6 Kc7 43. Rg6 1 : 0 Jobava – 曾重生 (Céng Chóngshēng), 9th “弈诚杯” (“Yìchéng Cup”) Chinese Chess League, 天津 (Tiānjīn) 2013. 15. Qd4. 15. Qxd5 b5! would lead to nowhere, but 15. Qd2!? Qh3 16. Kf2 Be6 17. Nc3 might have offered more opportunities for an advantage. 15. ... Be6 16. Qf4 Qh3 17. Qh4 Qxh4 18. gxh4 f6 19. exf6 Rxf6+ 20. Ke3 Re8 21. Nc3 Bg4+ 22. Kd3 Bxe2+ 23. Nxe2 Rf3+ 24. Kd2 Rf2 25. Rae1 d4 26. Kd1 Re3 27. h3 c5 28. b3 Kf7 29. Nc1

29. ... Kf6? (29. ... Ref3! 30. Re5 Rb2 31. Rxc5 Rff2=) 30. Rxe3 dxe3 31. Ne2 Ke5 32. Rg1 Rf7 33. Rg5+ Ke4 34. Rg4+ Ke5 35. Nc3 Rf3 36. Rxg7 Rxh3 37. Rxh7 Rh2 38. Rxb7 Rh3 39. Rh7 Rh2 40. Rb7 Rxh4 41. Ke2 1 : 0.

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