的嗒糖

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Just two lines by Goofy

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Radoslaw Wojtaszek – Fabiano Caruana
77th Tata Steel Chess Tournament; Rotterdam, January 15, 2015
Dutch Defence A88

1. d4 f5 2. c4 Nf6 3. g3 g6 4. Bg2 Bg7 5. Nf3 0-0 6. 0-0 d6 7. Nc3 c6 8. Re1 Na6 9. b3 Ne4 10. Bb2 Nxc3 11. Bxc3 Nc5 12. Ng5!? A novelty. The alternative 12. Nd2 d5 is roughly even, 赵雪 (Zhào Xuě) – M. Bartel, 41st Women’s Chess Olympiad, Tromsø 2014. 12. ... d5 13. Nh3 Ne4 14. Bb2 Be6 15. Nf4 Bf7 16. cxd5 cxd5 17. Nd3 a5 18. a4 b5!? Perhaps a little too ambitious. Black is willing to give up a Pawn of minor importance hoping to get up some sort of an attack on the Kingside. Worth considering was 18. ... Rc8 19. e3 Rc6 20. Rc1 Rxc1 21. Qxc1 Qb6 22. Qc2 Nd6 23. Rc1 Rc8 24. Qd1 Rxc1 25. Bxc1 with an edge for White (Monokroussos’ analysis). 19. axb5 Qb6 20. e3 Rfb8 21. Bf1 Qxb5 22. Ra3 Qe8 23. f3 Nd6 24. Qa1. Mounting pressure against the a5-Pawn. 24. ... g5 25. Bc3 g4 26. f4 Ne4 27. Bxa5 h5 28. Rc1 h4 29. Be1 Bf6 30. Nc5 hxg3 31. hxg3 Nxc5 32. Rxc5. White stands better; furthemore he is a Pawn ahead. With only 5 minites on the clock against opponent’s 45, Fabi skilfully finds a clever resource:

32. ... e5! 33. Rxa8!?? After long thought, Wojtaszek maximizes his practical chances of winning the game by playing a move which is not objectively the best one! The first choice of engines is 33. fxe5! Rxa3 34. Qxa3 Be7 35. Qb2! Bxc5 36. dxc5 with overwhelming compensation for the Exchange. 33. ... Rxa8 34. Qb1 exd4 35. Qxf5 Qxe3+? This move seems quite natural, but is actually inaccurate. After the less obvious 35. ... Qe6! 36. Qxe6 Bxe6 Black has good survival prospects. 36. Bf2 Qe6. Too late! 37. Bd3 Qxf5 38. Bxf5 Ra1+. Fabi found himself in time trouble and eventually it won the vertigo-dread of losing control. Here or on the next move Black should have played 38. ... Ra3. 39. Kg2 d3? 39. ... Ra3 was compulsory as the consequences of 40. b4 d3 are double-edged. 40. Bxd3 d4 41. b4 Bb3? A much cooler resistance results from 41. ... Ra4 42. b5 Rb4 seeking some chances of salvation. 42. b5+- Be7 43. Rh5 Rd1 44. Be2 Rd2 45. Bxg4 Rb2 46. Bf3 Bb4 47. b6! 1 : 0. For if 47. ... Be1 then 48. b7 Bf7 (48. ... Bxf2 loses to 49. b8=Q+ and 48. ... Rxf2+ fails to 49. Kg1 Rxf3 50. b8=Q+) 49. b8=Q+ Rxb8 50. Rg5+ Kf8 51. Bxe1 finis.

Fabiano Caruana
Photo: 彭肇勤 (Péng Zhàoqín)