中国女孩 (China Girl)

Viktor Lvovich Kortschnoi – 侯逸凡 (Hóu Yìfán)
5th György Marx Memorial; Paks, August 11, 2007
Catalan Opening E06

1. Nf3 Nf6 2. g3 e6 3. Bg2 d5 4. 0-0 Be7 5. d4 0-0 6. c4 dxc4 7. Qc2 a6 8. Qxc4 b5 9. Qc2 Bb7 10. Bd2 Be4 11. Qc1 Bb7 12. Bf4 Bd6 13. Nbd2 Nbd7. The alternative is 13. ... Nd5 14. Be5 Nd7 15. Nb3 a5 16. Nc5 Bxc5 17. dxc5 Ra6 18. Rd1 Qe7 19. e4 N5f6 20. Bxf6 (20. Bxc7 Nxc5) 20. ... Nxf6 21. Nd2 e5 22. a4 bxa4 23. Rxa4 Bc6 24. Ra1 Raa8 25. Qc2 a4 26. b4 axb3 27. Nxb3 Ba4 28. Ra3 Nd7 29. Rc1 Rfb8 30. Qc3 Bxb3 31. Rxa8 Rxa8 32. Qxb3 Rb8 33. Qa4 Nf8 34. Bh3 g6 35. c6 Rb2 36. Qa7 Qd6 37. Qc5 ½ : ½ P. H. Nielsen – 侯逸凡 (Hóu Yifán), 4th NH Chess Tournament, Rising Stars vs. Experience, Amsterdam 2009. 14. Nb3 Bd5 15. Rd1 (15. Nc5 Qe7 16. Nxd7 Nxd7=) 15. ... Qe7 16. Ne5 Bxg2. Not 16. ... Rfc8 because of 17. Nc6 Qe8 18. Nba5 and Black’s game is cramped. 17. Kxg2 Nd5 (17. ... Bxe5? 18. dxe5 Nd5 19. Bg5±) 18. Nc6. If 18. Nxd7 then 18. ... Qxd7 (18. ... Nxf4+ 19. gxf4 Qxd7 20. e4 f5 21. e5 Be7) 19. Bd2 f5 with a dynamic balance (Kramnik’s analysis). 18. ... Nxf4+! Copyright and puntuaction by Vladimir Borisovich Kramnik. Both 18. ... Qf6 19. Bxd6 cxd6 20. e4 [20. Qd2 Qg6 21. Rac1 f5 22. Nb4 N7f6 23. Nxd5 Nxd5= Lastin – 赵骏 (Zhào Jún), 4th Aeroflot Open, Moscow 2005] 20. ... N5b6 21. Nba5 and 18. ... Qe8 19. e4 Nxf4+ 20. gxf4 give White a sligt edge. 19. Qxf4. Not 19. gxf4? on account of Qh4 with the initiative. 19. ... Qe8 20. Qf3. Both 20. Qe3 and 20. Qd2 are equally answered by 20. ... f5. 20. ... f5! 侯逸凡 (Hóu Yìfán)’s novelty! The historic reference was 20. ... e5? 21. dxe5 Nxe5 22. Nxe5 Qxe5 23. Rd2 Rae8! 24. e3 Re6! (Kasparov – Kramnik, London 2000, Classical World Chess Championship match game 15) and now, according to Kramnik, both 25. Rc1!? and 25. Qd5 should give White a slight but lasting advange. 21. Rac1. Neither 21. e3 g5! nor 21. Nba5 Nf6 would cause Black any worries. 21. ... Nf6 22. Kh1 Kh8 23. Nba5 Qg6 24. Ne5 Bxe5 25. dxe5 Ng4 26. h3. If 26. Rxc7 then 26. ... Qh5 27. Qg2 (not 27. h4? because of 27. ... f4 with powerful attack) 27. ... Nxe5 with equality. 26. ... Nxe5 27. Qe3 Qf6 28. Rxc7 h6. If 28. ... f4 then 29. Qxf4 Qxf4 30. gxf4 Rxf4 31. Ra7 Raf8 32. Rxa6 (32. f3 Ra4) 32. ... Rxf2 (or 32. ... Ra4 33. Rxe6) 33. Rxe6 with an edge for White. Also after 28. ... Rf7 29. Qc3 White stands a bit better. 29. f4 Nf7 30. Rdd7 Rad8 31. Qc3! Rxd7 32. Rxd7 Qxc3 33. bxc3. The ending is slightly favourable to White. 33. ... e5 34. e3 exf4 35. exf4 g5 36. Nc6 gxf4 37. gxf4 Rc8 38. Na7 Rf8 39. Kg2 Kg7 40. Nc6 Kf6 41. Ra7 Nd6 42. Rxa6 Ke6 43. Kf3 Rg8 44. Rb6 Rc8 45. Ke2 Ra8 46. Nd4+ Kd5 47. Nxb5 Rxa2+ 48. Kd3 Ne4 49. Nd4 Rd2+? (49. ... Ra3 50. Nb5 Ra1 51. Rxh6 Rd1+ 52. Ke2 Rg1!=) 50. Ke3 Rh2 51. Rxh6 Nd6 52. Kf3 Rd2 53. Rf6? (53. c4+! Nxc4 54. Nxf5+−) 53. ... Rd3+! 54. Kg2 Rd2+ (54. ... Rxc3?? 55. Rxd6+!+−) 55. Kf1

55. ... Ne4!!= 56. Rxf5+ Kc4 57. Kg1 Nxc3 58. Nf3 Ra2 59. Rf8 Ne2+ 60. Kf2 Nd4+ 61. Kg3 Ra3 62. Rc8+ Kb5 63. Kg4 Rxf3 64. Rd8 Rxf4+ 65. Kxf4 Ne6+ 66. Ke5 Nxd8 67. Kf6 Kc6 68. h4 Kd7 ½ : ½.