Stronghold

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Concisely annotated by Money Mouse

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丁立人 (Dīng Lìrén) – 周唯奇 (Zhōu Wéiqí)
5th International Tournament; 儋州 (Dānzhōu), June 30, 2014
Bogo-Indian Defence E11

1. d4 Nf6 2. c4 e6 3. Nf3 d5 4. g3 Bb4+ 5. Bd2 Bxd2+ 6. Nbxd2 0-0 7. Bg2 Nbd7 8. 0-0 c5. For 8. ... Qe7 9. Qc2 see Capablanca – Marshall, New York 1927. 9. Rc1 b6 10. cxd5 Nxd5 11. Ne4 Qe7 12. Ne5 Nxe5 13. dxe5 f6 14. exf6 gxf6 15. Nc3 Nxc3 16. Rxc3 Bb7 17. Bxb7 Qxb7 18. Rd3 Qe4 19. Qd2 Rae8 20. Rd1 Re7 21. b3 Kg7 22. a4 e5 23. Rc1 Rff7 24. Rd6 Qf5 25. Rd1 Rc7 26. Qd5 c4 27. e4 Qf3 28. bxc4 Qb3. It’s perhaps more flexible 28. ... Qe2, in order to meet 29. Qe6 by 29. ... Qxe4 (and of course if 30. R6d4 then 30. ... Qxd4). 29. Qe6. With the feral threat of 30. Qg4+ Kh6 31. h4! and then Qg4-g5 mate.

29. ... h5? It strikes me that the “self-critical” 29. ... Qf3 would have been more stubborn, although after 30. Qd5! (far better than 30. Rd7) 30. ... Rc5 31. Qe6 Rc6 32. Rxc6 Qxd1+ 33. Kg2 White would hold a powerful grip. 30. Qf5+- Qxc4 31. Qxh5 Qxe4 32. Rd8 Qxa4 33. g4 Rf8 34. g5 fxg5 35. Rxf8 Kxf8 36. Rd8+ 1 : 0.

Final Destination

周唯奇 (Zhōu Wéiqí) – 侯逸凡 (Hóu Yìfán)

兴化 (Xīnghuà), 27 aprile 2013

Attacco Indiano A08

1. Cf3 Cf6 2. g3 d5 3. Ag2 e6 4. 0-0 Ae7 5. d3 0-0 6. Cbd2 c5 7. e4 Cc6 8. Te1 b5 9. e5 Cd7 10. Cf1 a5. Per 10. ... b4 cfr. Harikrishna – 侯逸凡 (Hóu Yìfán), Wijk aan Zee 2008. 11. h4 b4 12. C1h2. Lo storico precedente 12. Af4 a4 13. a3! “come nella partita Fischer – Mjagmarsuren, Sousse, Torneo Interzonale 1967, porta ad un gioco a doppio taglio, in cui le possibilità del Nero sull’ala di Donna compensano l’attacco del Bianco sull’ala di Re... ma di solito il Bianco arriva prima”. (Bobby Fischer, “60 partite da ricordare”, Milano, U. Mursia & C., 1972, p. 8). 12. ... Aa6 (12. ... a4 13. Ah3 a3 14. b3±) 13. Cg4. Per 13. Ag5 cfr. Andreikin – 侯逸凡 (Hóu Yìfán), Gaziantep 2008. 13. ... Tc8!? Più solite sono 13. ... a4 14. Ag5 Cd4 15. Dd2 Cxf3+ 16. Axf3 c4 17. d4 c3?! (17. ... Tb8∞) 18. bxc3 bxc3 19. De3 Tb8 (19. ... Axg5 20. hxg5 Dc7 21. Rg2 Tfb8 22. Th1 Cf8 23. Cf6+! Rh8 24. Cxh7!+) 20. Tab1! Tb2 21. Axe7 Dxe7 22. Dxc3 Txa2 23. Ce3!± Chuchelov – Muir, Berlino 1998 e 13. ... Cd4!? 14. c3 (Uhlmann ha poi propugnato 14. Cxd4 cxd4 15. b3!? Dc7 16. Ab2 h5!? 17. Ch2 Cxe5 18. Axd4 Cc6 19. Ab2 g6=) 14. ... Cxf3+ 15. Axf3 Tb8 16. Af4 a4! 17. Dd2 a3! con l’iniziativa, Lau – Uhlmann, Potsdam 1988. 14. h5 a4 15. h6 g6 16. a3 Ab5 17. Af4 Cd4 18. Dd2? Blackout. Era di prammatica 18. Cxd4 cxd4 con equivalenza. 18. ... Cxf3+ 19. Axf3 g5. Sic et simpliciter. L’Alfiere è intrappolato. 20. Ae3 d4 21. Axd4 cxd4 22. axb4 Cb6 23. Tac1 Rh8 24. Ted1 Cd5 25. c4 dxc3 26. bxc3 Ac6 27. b5 Aa8 28. c4 f5 29. exf6 Cxf6 30. Ce5 Axf3 31. Cxf3 (31. Dxg5 Ch5-+) 31. ... Cg4 32. De2 Cxf2? Un miraggio. Era consequenziale 32. ... Tc5! (Δ ... Tc5-f5) 33. Db2+ Af6-+. 33. Dxf2 g4 34. Db2+ Af6 35. Ce5 a3 36. Dc3 Db6+ 37. Rg2? (37. c5! Dxb5) 37. ... Db7+? Uno scacco controproducente! Dopo 37. ... De3! il vantaggio del Nero è solare. 38. Rh2 Db8 39. Te1 Tc5 40. d4 Axe5 41. dxe5 a2? (41. ... Tf5!) 42. Tf1 Rg8 (42. ... Tfc8 43. Tc2 Dc7 44. Txa2 Txc4 45. Taf2+-) 43. Dd4 Tc7 44. b6 Te7 45. c5 Td8 46. Dxg4+ Rh8 47. Dg5 Tde8 48. Df6+ Rg8 49. Tc4 1 : 0.

侯逸凡 (Hóu Yìfán)
Foto: sports.sina.cn

Alone in a Crowd

周唯奇 (Zhōu Wéiqí) – 侯逸凡 (Hóu Yìfán)
45th Chinese Chess Championship; 兴化 (Xīnghuà), May 26, 2010
Queen’s Gambit Declined D38

1. d4 e6 2. c4 d5 3. Nf3 Nf6 4. Nc3 Bb4 5. cxd5 exd5 6. Bg5 h6 7. Bxf6 Qxf6 8. Qb3 c5 9. dxc5 Bxc3+ 10. bxc3 0-0 11. Nd4 Be6 12. Qxb7 (12. Qa3 Rc8 13. e3 Nd7 14. c6 bxc6 15. Ba6 Rcb8 16. 0-0 Rb6 17. Be2 Qg6 18. Nxe6 Qxe6 19. Rab1 Rab8 20. Rb3 Nf6 21. Bd1 Qd7 22. Bf3 ½ : ½ Ivanchuk – Mitkov, 5th World Team Chess Championship, Yerevan 2001) 12. ... Nd7 13. c6 Rab8 14. Qxa7 (13. Qb4 Rab8 14. Qa3 Rfc8 15. e3 Qg6 leaves Black with powerful compensation: 16. f3 Nxc5 17. Kf2 Qf6 18. Rc1 Qe7 19. Kg1 Bd7 20. Re1 Rb1 21. Re2 Rcb8 22. g4 h5 23. h3 Qh4 24. Kg2 Nd3 25. Qd6 Ne1+ 26. Kg1 R8b6 27. Qe5 Rd1 28. Rhh2 Nd3 29. Qc7 Rbb1 0 : 1 Akobian – Mitkov, 17th Open, Chicago 2008) 14. ... Ra8 15. Qc7 Ne5 16. e3. Not 16. f3 on account of 16. ... Qf4! 17. Nxe6 Qe3! with irresistible attack (18. Nxf8 Nd3+ 19. Kd1 Rxa2!−+). 16. ... Rfc8

17. Qb6? This just opens the doors to Black’s breakthrough. Correct was 17. Qd6! Rxc6 18. Qb4 (18. Nxc6? Ng4!−+) 18. ... Ng4 19. Qb2 Rxc3! 20. Bb5 Rb3! 21. axb3 Qxf2+ 22. Qxf2 Rxa1+ 23. Ke2 Ra2+ with approximate equality. 17. ... Rcb8 18. Qc5 Rb2 19. f4 Rxg2 20. 0-0-0 Rgxa2 21. Be2 Nc4 22. Bxc4 dxc4 23. Rhg1 Ra1+ 24. Kd2 R8a2+ 25. Nc2 Rxd1+ 0 : 1.